hdu——1062Text Reverse（反转函数reverse）-白红宇

hdu——1062Text Reverse（反转函数reverse）

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发布时间：2019-05-25

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Text Reverse

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 25706 Accepted Submission(s): 9959

Problem Description

Ignatius likes to write words in reverse way. Given a single line of text which is written by Ignatius, you should reverse all the words and then output them.

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.

Each test case contains a single line with several words. There will be at most 1000 characters in a line.

Output

For each test case, you should output the text which is processed.

Sample Input

olleh !dlrow

m'I morf .udh

I ekil .mca

Sample Output

hello world!

I'm from hdu.

I like acm.

Hint

Remember to use getchar() to read '\n' after the interger T, then you may use gets() to read a line and process it.

Author

Ignatius.L

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注意最后一部份也要反转

#include
   
    #include
    
     #include
     
      #include
      
       using namespace std;int main(){	long long m,n;	string a;	cin>>n;	getchar();	while(n--)	{		m=0;		getline(cin,a);		while(a.find(" ",m)!=string::npos)		{			reverse(a.begin()+m,a.begin()+a.find(" ",m));			m=a.find(" ",m)+1;		}		reverse(a.begin()+a.find_last_of(" ")+1,a.end());		cout<
       <